TI-84 Plus Lesson – Module 13.1: Critical Points | TI
...aximum value and an absolute minimum value on the interval. This theorem says that a continuous function that is defined on a closed interval must have both an absolute maximum value and an absolute minimum value. It does not address how to find the extreme values. Local Extreme Values of a ...https://education.ti.com/en/product-resources/t3-free-courses/calculus84-online/mod13/mod13-lesson1
TI-84 Plus Lesson – Module 13.4: TI-84 Min/Max Feature | TI
... Graph Y1 = X2 in a [-3, 3, 1] x [-5, 5, 1] window. Use the Minimum feature in the CALCULATE menu to find the local minimum. Leaving the cursor away from (0,0) for your initial guess. The calculator provides approximations that are given in exponential notatio...https://education.ti.com/en/product-resources/t3-free-courses/calculus84-online/mod13/mod13-lesson4
TI-89 Lesson – Module 16.2: Visual Area Functions | TI
...he Fundamental theorem applies. Click here to see the answer. Visualizing Suppose that you don't know a formula for the curve function but you have its graph. You can determine the shape of the area function by analyzing the graph of the curve. Below is the graph of on the interval from...https://education.ti.com/en/product-resources/t3-free-courses/calculus89-online/mod16/mod16-lesson2
TI-84 Plus Lesson – Module 13.3: The Second Derivative Test | TI
...native to the first derivative test for analyzing critical points where the first derivative is zero. Recall that the second derivative describes concavity. If the graph of f(x) is concave upward or concave downward at a point where the graph has a horizontal tangent line, then there is a local...https://education.ti.com/en/product-resources/t3-free-courses/calculus84-online/mod13/mod13-lesson3
TI-89 Lesson – Module 16.3: Fundamental Theorem of Calculus | TI
... in this lesson along with a corollary that is used to find the value of a definite integral analytically. Restating the Fundamental Theorem You have discovered the Fundamental Theorem in the context of finding areas under a curve but a more general version of this theorem can be proved witho...https://education.ti.com/en/product-resources/t3-free-courses/calculus89-online/mod16/mod16-lesson3
Module 16 - Answers
... Answer 5 16.2.5 The height of the curve is increasing, so the slopes of the area function are increasing and its graph is concave upward. An approximate area function graph is shown below. The actual values of the area function are not as important as the graph's shape. ...https://education.ti.com/en/product-resources/t3-free-courses/calculus89-online/mod16/mod16-answers
Planning for Success Sweepstakes Official Rules
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