Accelerated Student Learning Program | Texas Instruments
...orkshops AcceleratedStudent LearningProgram Move students through pandemic learning disruptions and put them on a path for building a strong foundation in grade-level mathematics. Professional learning that meets you where you are....https://education.ti.com/en/educators/district-school-leader-resources/accelerated-student-learning
TI-84 Plus Module 13: Extreme Values Self-Test | TI
...ng graph shows the first derivative of a function g along with its zero in a [-4.7, 4.7, 1] x [-3.1, 3.1, 1] window. What does the graph tell you about the extreme points of g on the interval (-1,2)? The following graph shows the second derivative o...https://education.ti.com/en/product-resources/t3-free-courses/calculus84-online/mod13/mod13-selftest
Module 13 - Extreme Values of Functions
...1 Answer 1 13.1.1 As shown in the previous example, the function has only one critical point, which occurs at x = 0. The values of the output at the critical point and at the endpoints are f(-4) = 16, f(0) = 0 and f(2) = 4. The function has: an absolute and a local maximum o...https://education.ti.com/en/product-resources/t3-free-courses/calculus84-online/mod13/mod13-answers
TI-84 Plus Lesson – Module 13.4: TI-84 Min/Max Feature | TI
...| Lesson 4 | Self-Test TI-84 Plus Graphing Calculator Calculus LessonModule 13: Extreme Values of Functions .colcautiontext{width:250px;padding: 1px 0px 0px 50px;} .colcaution{background-image:url("http://education.ti.com/images/online_courses/t3/calculus/i...https://education.ti.com/en/product-resources/t3-free-courses/calculus84-online/mod13/mod13-lesson4
TI-84 Plus Lesson – Module 13.2: The First Derivative Test | TI
...nimum at the critical point The First Derivative Test for Neither As discussed at the end of Lesson 13.1, x = 0 is a critical point of f(x) = x3 but there is no local extremum there. It was noted that the first derivative (slope of the tangents) is positive on both sides of the critical poi...https://education.ti.com/en/product-resources/t3-free-courses/calculus84-online/mod13/mod13-lesson2
TI-89 Lesson – Module 16.2: Visual Area Functions | TI
...en t = 1 and t = x can be found by evaluating the definite integral . For example, if x = 3 the area under the curve between x = 1 and x = 3 is about 1.09861, as illustrated and evaluated in the screens below. 16.2.1 Put your calculator in Approximate mode or just press to get th...https://education.ti.com/en/product-resources/t3-free-courses/calculus89-online/mod16/mod16-lesson2
TI-89 Lesson – Module 16.1: Symbolic Area Functions | TI
...as the number of rectangles approached infinity. Finding Area Find the area under the curve f(x) = x2 between x = 0 and x = 2. Execute NewProb Define f(x) = x2 Take the limit of the function rrs to find the exact area under the curve between x = 0 an...https://education.ti.com/en/product-resources/t3-free-courses/calculus89-online/mod16/mod16-lesson1