Module 24 - Answers | ||||
Lesson 1 | ||||
Answer 1 | ||||
24.1.1
The dot product is the sum of the product of the first components in each vector and the product of the second components: [a1, a2]·[b1, b2] = a1b1 + a2b2. |
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Answer 2 | ||||
24.1.2
[2, 1, -4] x [-1, -2, 1] = [-7, 2, -3] = -7i + 2j -3k Alternatively, you can directly compute crossP([2, 1, -4], [-1, -2, 1]) without storing the vectors to a and b. The vector [-7, 2, -3] is perpendicular to both [2, 1, -4] and [-1, -2, 1]. |
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Lesson 2 | ||||
Answer 1 | ||||
24.2.1
The particle follows an elliptical path. |
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Answer 2 | ||||
24.2.2
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Answer 3 | ||||
24.2.3
The velocity vector points in a direction that is parallel to the tangent to the curve at the point when |
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Answer 4 | ||||
24.2.4
For the motion, the acceleration vector points opposite the direction of position vector. |
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Lesson 3 | ||||
Answer 1 | ||||
24.3.1
The projectile reaches its highest point about 1.9 seconds after it was fired and it is slightly more than 59 feet above the ground, as shown by the y coordinate. |
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Answer 2 | ||||
24.3.2
The projectile reaches its highest point about t = 1.924 seconds after it was fired. |
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Answer 3 | ||||
24.3.3
The maximum height of the projectile is about 59.22 ft. |
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Self Test | ||||
Answer 1 | ||||
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Answer 2 | ||||
-10 | ||||
Answer 3 | ||||
[0,0,-10] | ||||
Answer 4 | ||||
[-15,15] x [-15,15] |
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Answer 5 | ||||
The maximum height occurs about 3.7 or 3.8 seconds after the projectile was launched. |
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