Module 24 - Answers
 
Lesson 1
 
 Answer 1
 
24.1.1  

The dot product is the sum of the product of the first components in each vector and the product of the second components: [a1, a2]·[b1, b2] = a1b1 + a2b2.

 
 Answer 2
 
24.1.2  

[2, 1, -4] x [-1, -2, 1] = [-7, 2, -3] = -7i + 2j -3k

Alternatively, you can directly compute crossP([2, 1, -4], [-1, -2, 1]) without storing the vectors to a and b.

The vector [-7, 2, -3] is perpendicular to both [2, 1, -4] and [-1, -2, 1].

 
Lesson 2
 
 Answer 1
 
24.2.1

The particle follows an elliptical path.

 
 Answer 2
 
24.2.2  

 
 Answer 3
 
24.2.3  

The velocity vector points in a direction that is parallel to the tangent to the curve at the point when
t = /4: The point on the curve in this case is .

 
 Answer 4
 
24.2.4  

For the motion, the acceleration vector points opposite the direction of position vector.

 
Lesson 3
 
 Answer 1
 
24.3.1

The projectile reaches its highest point about 1.9 seconds after it was fired and it is slightly more than 59 feet above the ground, as shown by the y coordinate.

 
 Answer 2
 
24.3.2

The projectile reaches its highest point about t = 1.924 seconds after it was fired.

 
 Answer 3
 
24.3.3

The maximum height of the projectile is about 59.22 ft.

 
Self Test
 
 Answer 1
 

 
 Answer 2
 
-10
 
 Answer 3
 
[0,0,-10]
 
 Answer 4
 

[-15,15] x [-15,15]

 
 Answer 5
 

Solved Graphically Solved Analytically

The maximum height occurs about 3.7 or 3.8 seconds after the projectile was launched.

 
 

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