Module 19 - Exponential Growth and Decay

Module 19 - Answers

Lesson 1

Answer 1

19.1.1 The amount will double in about 8.7 years.

Answer 2

19.1.2 The amount will be $97,948.10 in 35 years.

Lesson 2

Answer 1

19.2.1

solve(tl = (tlo - ts)*e^(-k*t) + ts,k) | tl=14 and t=30

tl = (tlo - ts)*e^(-k*t) + ts,k) | and t=60

Lesson 3

Answer 1

19.3.1

solve(v = 7.93407*e^(k*t), k) | t = 50 and v = 0.876679

This value of k is very close to the previous value found using the values t = 30 and v = 2.0928. The graph using this value of k also fits the data well.

Answer 2

19.3.2 Half of the voltage is released by t = 15.753 seconds.

Self Test

Answer 1

The investment will double in about 13.9 years.

Answer 2

The amount will be $36,945.30 in 25 years.

Answer 3

0.085923

Answer 4

The temperature of the water is 11.4557°C after 60 minutes.

Answer 5

-0.055181

Answer 6

The half-life of the capacitor is about 12.6 seconds.