Module 7 - Answers Lesson 1 Answer 1 7.1.1 The average velocity from t = 0 to t = 0.16 was –0.93125. The average velocity from t = 0.16 to t = 0.28 was –2.18333.  Answer 2 7.1.2   The book fell faster during the subinterval from t = 0.16 to t = 0.28.  Lesson 2 Answer 1 7.2.1 Average velocities: –2.1 m/s; –1.933 m/s; –1.75 m/s   Answer 2 7.2.2 The best approximation is –1.75 m/s, which is the average velocity for the interval (0.16, 0.716) to (0.18, 0.681). It best approximates the instantaneous velocity because the elapsed time interval is the smallest of the three.  Answer 3 7.2.3     Lesson 3 Answer 1 7.3.1 –1.64509 m/s; –1.64914 m/s; –1.64955 m/s  Answer 2 7.3.2 Yes. This average velocity is also –1.6496 m/s, which is equal to the instantaneous velocity.  Self Test Answer 1 The ball averaged approximately 0.6 m/s over the interval from t = 0.16 to t = 0.48, traveling in an upward direction. Answer 2 Answer 3 2.1401 m/s Answer 4 Answer 5 2.1447 m/s Answer 6 2.1447 m/s; The ball was traveling approximately 2.1447 m/s at t = 0.16 in an upward direction. ©Copyright 2007 All rights reserved. | Trademarks | Privacy Policy | Link Policy