Module 5 - Answers |
Lesson 1 |
Answer 1 |
5.1.1
It appears that:
Vertical asymptote: x = 3 You cannot really be sure from the graph. You need to apply analytic techniques as we will illustrate. |
Answer 2 |
5.1.2 As x approaches 3 from the left, the function values are negative and their absolute values increase without bound. Symbolically, as x 3, f(x) . As x approaches 3 from the right, the function values are positive and increase without bound. Symbolically, as, x 3+, f(x) |
Answer 3 |
5.1.3
Because the values of the function in absolute value increase without bound as x approaches 3 from the left and from the right, x = 3 is a vertical asymptote. Notice that means as x 3, f(x) means as, x 3+, f(x) |
Answer 4 |
5.1.4 The tables show that as the magnitude (absolute value) of the x-coordinates increases, the y-coordinates approach 2. Symbolically, f(x) 2 as x and as x . |
Lesson 2 |
Answer 1 |
5.2.1
Because , which is not or , x = 2 is not a vertical asymptote. |
Answer 2 |
5.2.2
Because , there is a hole at x = 3 and not a vertical asymptote there.
Because and , x = 2 is a vertical asymptote.
The Window values shown are [7.9, 7.9] x [10, 10] with xres = 1. There is a tiny hole at and x = 2 is a vertical asymptote. Because xres is 1 and a pixel represents x = 2, the calculator evaluated the function at x = 2 and determined that the function was not defined there. That is why there is no vertical line shown at x = 2. |
Lesson 3 |
Answer 1 |
5.3.1
Because the function does not approach a finite real number as the magnitude of x gets large without bound, no horizontal line is an asymptote. |
Answer 2 |
5.3.2
The vertical asymptote is x = 2 and the oblique asymptote is y = x + 2. In a large window the graph of is similar to y = x + 2, the oblique asymptote. In a window near x = 2 the graph is similar to .
The Window shown is [30, 30] x [30, 30], xscl = yscl = 5, and the oblique asymptote y = x + 2 is shown as a dotted line. The style of a selected graph may be chosen from the Style menu, which is displayed by pressing in the Y= editor while the function in question is highlighted. The style of y = x + 2 was chosen to be dotted.
The Window shown is [0, 4] x [25, 25]. The graph of is shown as a dotted curve. |
Lesson 4 |
Answer 1 |
5.4.1 |
Answer 2 |
5.4.2 The graph of looks like the graph of the parabola y = x2 8x 15 in a large viewing window and like the graph of in a smaller window near x = 2. |
Self Test |
Answer 1 |
The two horizontal asymptotes of this function are y = 1 and y = 1. |
Answer 2 |
Answer 3 |
[5, 5] x [5, 5] There appear to be vertical asymptotes at and but not x = 4 |
Answer 4 |
Answer 5 |
The graph of will resemble the graph of the line y = 3x + 7 in a large viewing window. It will resemble the graph of in a small window near x = 2. The graph of has a vertical asymptote at x = 2. |
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