Module 24 - Answers |
Lesson 1 |
Answer 1 |
24.1.1
1 + x 1 + x + x2 1 + x + x2 + x3 |
Answer 2 |
24.1.2
The graphs appear to coincide when x is between -0.5 and 0.5. |
Answer 3 |
24.1.3
|
Answer 4 |
24.1.4
The partial sums appear to converge to y = sin x. |
Answer 5 |
24.1.5
[-10,10,1] x [-50,250,50] As more terms are added, the interval where each partial sum matches ex widens. |
Lesson 2 |
Answer 1 |
24.2.1
f(-0.5) 0.60653 p(-0.5) = 0.625 f(0.5) 1.6487 p(0.5) = 1.625 In each case, the values of the function and the approximating polynomials are close. |
Answer 2 |
24.2.2
Letting f(x) = ln(1 + x), the table below lists the coefficients of the fifth-order Maclaurin polynomial.
The fifth-order Maclaurin polynomial approximates f(x) = ln(1 + x) for values of x close to 0. |
Answer 3 |
24.2.3
[-2, 2, 1] x [-3, 3, 1] |
Lesson 3 |
Answer 1 |
24.3.1
is the second-order Taylor polynomial for ln x centered at 1.
[0, 3, 1] x [-3, 1, 1] |
Answer 2 |
24.3.2
1 - (x - 1) + (x - 1)2 is the second-order Taylor polynomial for 1/x centered at 1.
[0, 3, 1] x [-1, 3, 1] |
Self Test |
Answer 1 |
The fifth-order Maclaurin polynomial for tan-1(x) is . |
Answer 2 |
The interval of convergence appears to be (-1,1).
[-2, 2, 1] x [-2, 2, 1] |
Answer 3 |
The second-order Taylor polynomial centered at 2 is for ex is . |
Answer 4 |
The fourth-order Maclaurin polynomial for ex2 is . |
Answer 5 |
[-2, 2, 1] x [-1, 5, 1] |
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