The doubling time is about 10.7 years for each initial amount. It appears the doubling time is independent of the initial amount. It only depends on the rate r.

The amount in the account at time t is given by A = 1000 e ^0.07t.

The investment will grow to approximately $97,948 in 35 years.

It will take about 6.4 years for the balance to reach $10,000.

After 60 minutes the water will be approximately 8.58° C.

If and V(0) = 7.93407, then V = 7.93407e^{k · t}.

k -0.0441 This value is very close to the previous value of k. The solution using this value of k fits the data very well.

The half-life is about 15.75 seconds.

The initial $5000 will be worth $36,945.28 in 25 years at 8% compounded continuously.

k 0.085923

k -0.055181