Module 20  Answers  
Lesson 1  
Answer 1  
20.1.1
One antiderivative appears to be , as confirmed by the graph of Y_{2} = X^{4} / 4 coinciding with the graph of .


Lesson 2  
Answer 1  
20.2.1


Answer 2  
20.2.2
For x = 1 and y = 1,


Answer 3  
20.2.3
The graph shown is that of , the solution of with y(1) = 1 which was found earlier. 

Lesson 3  
Answer 1  
20.3.1
You need 20 points to reach y(1) 1.95. 

Answer 2  
20.3.2
y(1.2) 1.2073. The actual value rounds to 1.2097. 

Lesson 4  
Answer 1  
20.4.1
In this slope field the slopes of segments in a given row are equal. In the previous slope field the slopes of segments in a given column were equal. This difference is due to the fact that the differential equation in this problem is a function of y, therefore the slopes depend on y, not x. 

Self Test  
Answer 1  
Y_{1} = fnInt(cos(T/2),T,0,X) [2 ,2 ,1] x [2, 2, 1]
Any integral of the form
is a member of the family of curves represented by
. 

Answer 2  
Answer 3  
[0, 1, 1] x [0, 15, 5] 

Answer 4  
y(3) 3.155. (The actual value rounds to 3.296.)  
Answer 5  
[3, 3, 1] x [2, 2, 1] 

©Copyright 2007 All rights reserved.  Trademarks  Privacy Policy  Link Policy 