Module 7 - Answers | ||||
Lesson 1 | ||||
Answer 1 | ||||
7.1.1
The vertical asymptote appears to be at about x = 3. The horizontal asymptote appears to be at about y = 2. |
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Answer 2 | ||||
7.1.2
As x approaches 3 from the left, the function values are negative with increasing magnitude. In other words, . As x approaches 3 from the right, the function values become larger without bound. In other words, . |
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Answer 3 | ||||
7.1.3
The tables show that as the magnitude of the x-coordinates increase, the y-coordinates get closer to 2. and |
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Lesson 2 | ||||
Answer 1 | ||||
7.2.1
Since the limit exists, x = -2 is not a vertical asymptote, but rather the x-coordinate of a hole. The coordinates of the hole are . |
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Answer 2 | ||||
7.2.2
Because and there is a vertical asymptote at x = 2. Because , there is a hole at (-3, 1.8).
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Lesson 3 | ||||
Answer 1 | ||||
7.3.1
Because is a vertical asymptote, y = x + 2 is an oblique asymptote, and the graph of resembles near x = 2.
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Lesson 4 | ||||
Answer 1 | ||||
7.4.1
The rational function has a vertical asymptote at x = 2. The polynomial y = x2 - 8x - 15 is a nonlinear asymptote for the rational function and the function resembles near x = 2. |
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Self Test | ||||
Answer 1 | ||||
y = 0 | ||||
Answer 2 | ||||
x = -3, x = 1 | ||||
Answer 3 | ||||
x = -3 | ||||
Answer 4 | ||||
x = 1 | ||||
Answer 5 | ||||
Answer 6 | ||||
has an oblique asymptote of y = 3x + 7 and it has a vertical asymptote at x = 2.
[-10, 10, 1] x [-100, 100, 10] Xres = 2 |
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