Module 18 - Answers | ||||||||||
Lesson 1 | ||||||||||
Answer 1 | ||||||||||
18.1.1
Because , and , it appears that the exponent of x in the antiderivative is one greater than the exponent of the original function and that the antiderivative is divided by the value of its exponent. Predict that is . |
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Answer 2 | ||||||||||
18.1.2
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Answer 3 | ||||||||||
18.1.3
The TI-89 results may appear to be different from your predictions, however they are algebraically equivalent to and , respectively. |
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Answer 4 | ||||||||||
18.1.4
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Lesson 2 | ||||||||||
Answer 1 | ||||||||||
18.2.1
then
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Answer 2 | ||||||||||
18.2.2
The family of curves
is shown in a [-4
, 4
] x [-10, 10] window with |
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Lesson 3 | ||||||||||
Answer 1 | ||||||||||
18.3.1
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Answer 2 | ||||||||||
18.3.2
The general solution is y = Cex .
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Answer 3 | ||||||||||
18.3.3
The solution to y' = 2x with y(2)=1 is y = x2 3. |
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Answer 4 | ||||||||||
18.3.4
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Lesson 4 | ||||||||||
Answer 1 | ||||||||||
18.4.1
y(3) = 6 |
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Answer 2 | ||||||||||
18.4.2
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Answer 3 | ||||||||||
18.4.3
Enter y1' = y1, not y1' = y, be sure to clear yi1, and use a [-3, 3] x [-5, 10] window.
Instead of parallel line segments in columns, line segments in rows are parallel. |
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Self Test | ||||||||||
Answer 1 | ||||||||||
The indefinite integral , displayed in a [-2 , 2 ] x [-5, 5] window, with C = -6, -4, -2, 0, 2, 4, 6. |
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Answer 2 | ||||||||||
y = (x3 3x2 + 6x 6)ex + C | ||||||||||
Answer 3 | ||||||||||
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Answer 4 | ||||||||||
y(3) = 3 ln(3) 3.29584 | ||||||||||
Answer 5 | ||||||||||
[-3, 3] x [-2, 2] |
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Answer 6 | ||||||||||
[-3, 3] x [-1, 3] |
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